Will Nathan Drake make this jump in the uncharted trailer?

Drake moves horizontally at the exact same time it takes to move vertically. This means that I can use horizontal motion to calculate time, and then use that amount of time in vertical motion to find its final vertical position.

When Drake makes his jump, he has to rise to a vertical position of zero meters; This is the location of the ramp and where I set the source. If this final value is less than zero meters, it will land Down Aircraft. And that would be bad.

Determining horizontal motion is not very difficult. Since it has a constant velocity, I can find its final horizontal position with the following equation:

Check it out: I know the starting x-position (x1 = 2.4 m) and the final x-position (x)2 = 0 m) so I can use x-velocity to solve the time it takes to complete the jump. (He is moving to the left, so it will be negative 3.37 m / s.)

Notice that we don’t see the full jump in the trailer, however, if we do, it will take 0.71 seconds to reach the rear ramp of the aircraft.

Now, I can use this time and plug in the vertical kinematic equation. This gives a final y-position Negative 1.79 m.

It is less than zero, so there is nothing but air beneath it. And remember: it’s bad.

We haven’t finished yet, but it’s worth taking a second to think about why it even ended Low Than he started. This is because although its initial velocity is positive (upward), the jump takes so long that the gravitational force stops its upward motion and forces it to go down faster and faster.